Symfony Profiler

SELECT
  t0.id AS id_5,
  t0.first_name AS first_name_6,
  t0.last_name AS last_name_7,
  t0.email AS email_8,
  t0.professional_email AS professional_email_9,
  t0.birth_day AS birth_day_10,
  t0.phone AS phone_11,
  t0.main_phone AS main_phone_12,
  t0.roles AS roles_13,
  t0.password AS password_14,
  t0.last_connection AS last_connection_15,
  t0.person_type AS person_type_16,
  t0.created_at AS created_at_17,
  t0.updated_at AS updated_at_18,
  t0.address_id AS address_id_19,
  t0.gender_id AS gender_id_20,
  t0.reference_status_id AS reference_status_id_21,
  t0.reference_marital_status_id AS reference_marital_status_id_22,
  t0.type,
  t1.cin AS cin_23,
  t1.is_recommender AS is_recommender_24,
  t1.cnss AS cnss_25,
  t1.rc AS rc_26,
  t1.professional_status AS professional_status_27,
  t1.subject_to_vat AS subject_to_vat_28,
  t1.created_qualifiqaution_date AS created_qualifiqaution_date_29,
  t1.company_name AS company_name_30,
  t1.common_company_identifier AS common_company_identifier_31,
  t1.qualification_level_id AS qualification_level_id_32,
  t1.sector_id AS sector_id_33,
  t1.manager_id AS manager_id_34,
  t1.status_id AS status_id_35,
  t1.sponsor_id AS sponsor_id_36,
  t1.nationality_id AS nationality_id_37,
  t2.count_agent_assignment_number AS count_agent_assignment_number_38
FROM
  abstract_collaborator t0
  LEFT JOIN agent t1 ON t0.id = t1.id
  LEFT JOIN manager t2 ON t0.id = t2.id
  LEFT JOIN manager_back_office t3 ON t0.id = t3.id
  LEFT JOIN manager_it t4 ON t0.id = t4.id
WHERE
  t0.professional_email = ?
LIMIT
  1

SELECT t0.id AS id_5, t0.first_name AS first_name_6, t0.last_name AS last_name_7, t0.email AS email_8, t0.professional_email AS professional_email_9, t0.birth_day AS birth_day_10, t0.phone AS phone_11, t0.main_phone AS main_phone_12, t0.roles AS roles_13, t0.password AS password_14, t0.last_connection AS last_connection_15, t0.person_type AS person_type_16, t0.created_at AS created_at_17, t0.updated_at AS updated_at_18, t0.address_id AS address_id_19, t0.gender_id AS gender_id_20, t0.reference_status_id AS reference_status_id_21, t0.reference_marital_status_id AS reference_marital_status_id_22, t0.type, t1.cin AS cin_23, t1.is_recommender AS is_recommender_24, t1.cnss AS cnss_25, t1.rc AS rc_26, t1.professional_status AS professional_status_27, t1.subject_to_vat AS subject_to_vat_28, t1.created_qualifiqaution_date AS created_qualifiqaution_date_29, t1.company_name AS company_name_30, t1.common_company_identifier AS common_company_identifier_31, t1.qualification_level_id AS qualification_level_id_32, t1.sector_id AS sector_id_33, t1.manager_id AS manager_id_34, t1.status_id AS status_id_35, t1.sponsor_id AS sponsor_id_36, t1.nationality_id AS nationality_id_37, t2.count_agent_assignment_number AS count_agent_assignment_number_38 FROM abstract_collaborator t0 LEFT JOIN agent t1 ON t0.id = t1.id LEFT JOIN manager t2 ON t0.id = t2.id LEFT JOIN manager_back_office t3 ON t0.id = t3.id LEFT JOIN manager_it t4 ON t0.id = t4.id WHERE t0.professional_email = 'manager.20@milkiya.ma' LIMIT 1;

SELECT
  t0.id AS id_1,
  t0.file_path AS file_path_2,
  t0.collaborator_id AS collaborator_id_3
FROM
  avatar t0
WHERE
  t0.collaborator_id = ?

SELECT t0.id AS id_1, t0.file_path AS file_path_2, t0.collaborator_id AS collaborator_id_3 FROM avatar t0 WHERE t0.collaborator_id = 20;

SELECT
  t0.id AS id_1,
  t0.ip_address AS ip_address_2,
  t0.browser AS browser_3,
  t0.is_accepted AS is_accepted_4,
  t0.accepted_at AS accepted_at_5,
  t0.collaborator_id AS collaborator_id_6
FROM
  cgu t0
WHERE
  t0.collaborator_id = ?

SELECT t0.id AS id_1, t0.ip_address AS ip_address_2, t0.browser AS browser_3, t0.is_accepted AS is_accepted_4, t0.accepted_at AS accepted_at_5, t0.collaborator_id AS collaborator_id_6 FROM cgu t0 WHERE t0.collaborator_id = 20;

SELECT
  g0_.id AS id_0,
  g0_.name AS name_1,
  g0_.code AS code_2
FROM
  gender g0_
ORDER BY
  g0_.id ASC
LIMIT
  10

SELECT g0_.id AS id_0, g0_.name AS name_1, g0_.code AS code_2 FROM gender g0_ ORDER BY g0_.id ASC LIMIT 10;

SELECT
  COUNT(g0_.id) AS sclr_0
FROM
  gender g0_

SELECT COUNT(g0_.id) AS sclr_0 FROM gender g0_;